提问



如何反序列化此XML文档:


<?xml version="1.0" encoding="utf-8"?>
<Cars>
  <Car>
    <StockNumber>1020</StockNumber>
    <Make>Nissan</Make>
    <Model>Sentra</Model>
  </Car>
  <Car>
    <StockNumber>1010</StockNumber>
    <Make>Toyota</Make>
    <Model>Corolla</Model>
  </Car>
  <Car>
    <StockNumber>1111</StockNumber>
    <Make>Honda</Make>
    <Model>Accord</Model>
  </Car>
</Cars>


我有这个:


[Serializable()]
public class Car
{
    [System.Xml.Serialization.XmlElementAttribute("StockNumber")]
    public string StockNumber{ get; set; }

    [System.Xml.Serialization.XmlElementAttribute("Make")]
    public string Make{ get; set; }

    [System.Xml.Serialization.XmlElementAttribute("Model")]
    public string Model{ get; set; }
}





[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlArrayItem(typeof(Car))]
    public Car[] Car { get; set; }

}





public class CarSerializer
{
    public Cars Deserialize()
    {
        Cars[] cars = null;
        string path = HttpContext.Current.ApplicationInstance.Server.MapPath("~/App_Data/") + "cars.xml";

        XmlSerializer serializer = new XmlSerializer(typeof(Cars[]));

        StreamReader reader = new StreamReader(path);
        reader.ReadToEnd();
        cars = (Cars[])serializer.Deserialize(reader);
        reader.Close();

        return cars;
    }
}


这似乎不起作用:-(

最佳参考


这里是工作版本。我将XmlElementAttribute标签更改为XmlElement,因为在xml中,StockNumber,Make和Model值是元素,而不是属性。我还删除了reader.ReadToEnd();(该函数读取整个流并返回一个字符串,因此Deserialze()函数不再使用读取器......位置在流的末尾。我也对命名采取了一些自由:)。[51]


这是课程:


[Serializable()]
public class Car
{
    [System.Xml.Serialization.XmlElement("StockNumber")]
    public string StockNumber { get; set; }

    [System.Xml.Serialization.XmlElement("Make")]
    public string Make { get; set; }

    [System.Xml.Serialization.XmlElement("Model")]
    public string Model { get; set; }
}


[Serializable()]
[System.Xml.Serialization.XmlRoot("CarCollection")]
public class CarCollection
{
    [XmlArray("Cars")]
    [XmlArrayItem("Car", typeof(Car))]
    public Car[] Car { get; set; }
}


反序列化功能:


CarCollection cars = null;
string path = "cars.xml";

XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));

StreamReader reader = new StreamReader(path);
cars = (CarCollection)serializer.Deserialize(reader);
reader.Close();


稍微调整一下的xml(我需要添加一个新元素来包装< Cars> ... Net对于反序列化数组很挑剔):


<?xml version="1.0" encoding="utf-8"?>
<CarCollection>
<Cars>
  <Car>
    <StockNumber>1020</StockNumber>
    <Make>Nissan</Make>
    <Model>Sentra</Model>
  </Car>
  <Car>
    <StockNumber>1010</StockNumber>
    <Make>Toyota</Make>
    <Model>Corolla</Model>
  </Car>
  <Car>
    <StockNumber>1111</StockNumber>
    <Make>Honda</Make>
    <Model>Accord</Model>
  </Car>
</Cars>
</CarCollection>

其它参考1


你怎么样只将xml保存到文件中,并使用xsd?[52]



  1. 将文件写入磁盘(我将其命名为foo.xml)

  2. 生成xsd:xsd foo.xml

  3. 生成C#:xsd foo.xsd /classes



Et voila - 和应该能够通过XmlSerializer读取数据的C#代码文件:


    XmlSerializer ser = new XmlSerializer(typeof(Cars));
    Cars cars;
    using (XmlReader reader = XmlReader.Create(path))
    {
        cars = (Cars) ser.Deserialize(reader);
    }


(包括项目中生成的foo.cs)

其它参考2


你有两种可能性。


方法1. XSD 工具





假设您在此位置拥有XML文件C:\path\to\xml\file.xml



  1. 打开开发人员命令提示符

    你可以在Start Menu > Programs > Microsoft Visual Studio 2012 > Visual Studio Tools中找到它
    或者,如果您有Windows 8,只需在开始屏幕
  2. 中键入开发人员命令提示符即可
  3. 键入cd /D "C:\path\to\xml"
  4. ,将位置更改为XML文件目录
  5. 输入xsd file.xml
  6. 从xml文件创建 XSD文件
  7. 输入xsd /c file.xsd
  8. 创建 C#类


那就是它!你已经在C:\path\to\xml\file.cs中从xml文件生成了C#类


方法2 - 粘贴特殊





必需的Visual Studio 2012+



  1. 将XML文件的内容复制到剪贴板

  2. 向您的解决方案添加新的空类文件( Shift + Alt + C )

  3. 打开该文件,然后在菜单中单击Edit > Paste special > Paste XML As Classes




那就是它!


用法






这个助手类的用法非常简单:


using System;
using System.IO;
using System.Web.Script.Serialization; // Add reference: System.Web.Extensions
using System.Xml;
using System.Xml.Serialization;

namespace Helpers
{
    internal static class ParseHelpers
    {
        private static JavaScriptSerializer json;
        private static JavaScriptSerializer JSON { get { return json ?? (json = new JavaScriptSerializer()); } }

        public static Stream ToStream(this string @this)
        {
            var stream = new MemoryStream();
            var writer = new StreamWriter(stream);
            writer.Write(@this);
            writer.Flush();
            stream.Position = 0;
            return stream;
        }


        public static T ParseXML<T>(this string @this) where T : class
        {
            var reader = XmlReader.Create(@this.Trim().ToStream(), new XmlReaderSettings() { ConformanceLevel = ConformanceLevel.Document });
            return new XmlSerializer(typeof(T)).Deserialize(reader) as T;
        }

        public static T ParseJSON<T>(this string @this) where T : class
        {
            return JSON.Deserialize<T>(@this.Trim());
        }
    }
}


你现在要做的就是:


    public class JSONRoot
    {
        public catalog catalog { get; set; }
    }
    // ...

    string xml = File.ReadAllText(@"D:\file.xml");
    var catalog1 = xml.ParseXML<catalog>();

    string json = File.ReadAllText(@"D:\file.json");
    var catalog2 = json.ParseJSON<JSONRoot>();

其它参考3


以下代码段应该可以解决问题(您可以忽略大多数序列化属性):


public class Car
{
  public string StockNumber { get; set; }
  public string Make { get; set; }
  public string Model { get; set; }
}

[XmlRootAttribute("Cars")]
public class CarCollection
{
  [XmlElement("Car")]
  public Car[] Cars { get; set; }
}


...


using (TextReader reader = new StreamReader(path))
{
  XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
  return (CarCollection) serializer.Deserialize(reader);
}

其它参考4


看看这是否有帮助:


[Serializable()]
[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlArrayItem(typeof(Car))]
    public Car[] Car { get; set; }
}





[Serializable()]
public class Car
{
    [System.Xml.Serialization.XmlElement()]
    public string StockNumber{ get; set; }

    [System.Xml.Serialization.XmlElement()]
    public string Make{ get; set; }

    [System.Xml.Serialization.XmlElement()]
    public string Model{ get; set; }
}


并且没有使用visual studio附带的xsd.exe程序来创建基于该xml文件的模式文档,然后再次使用它来创建基于模式文档的类。

其它参考5


我不认为.net对于反序列化数组很挑剔。第一个xml文档格式不正确。
没有根元素,虽然它看起来像。规范的xml文档具有根和至少1个元素(如果有的话)。在你的例子中:


<Root> <-- well, the root
  <Cars> <-- an element (not a root), it being an array
    <Car> <-- an element, it being an array item
    ...
    </Car>
  </Cars>
</Root>

其它参考6


如果您的.xml文件已在磁盘中的某处生成并且您已使用List<T>,请尝试此代码块:


//deserialization

XmlSerializer xmlser = new XmlSerializer(typeof(List<Item>));
StreamReader srdr = new StreamReader(@"C:\serialize.xml");
List<Item> p = (List<Item>)xmlser.Deserialize(srdr);
srdr.Close();`


注意:C:\serialize.xml是我的.xml文件的路径。您可以根据需要进行更改。

其它参考7


除了事实之外,Kevin的anser很好,在现实世界中,你经常无法改变原始的XML以满足你的需求。


对于原始XML也有一个简单的解决方案:


[XmlRoot("Cars")]
public class XmlData
{
    [XmlElement("Car")]
    public List<Car> Cars{ get; set; }
}

public class Car
{
    public string StockNumber { get; set; }
    public string Make { get; set; }
    public string Model { get; set; }
}


然后你可以简单地打电话:


var ser = new XmlSerializer(typeof(XmlData));
XmlData data = (XmlData)ser.Deserialize(XmlReader.Create(PathToCarsXml));

其它参考8


试试这个用于Xml序列化的通用类&反序列化。


public class SerializeConfig<T> where T : class
{
    public static void Serialize(string path, T type)
    {
        var serializer = new XmlSerializer(type.GetType());
        using (var writer = new FileStream(path, FileMode.Create))
        {
            serializer.Serialize(writer, type);
        }
    }

    public static T DeSerialize(string path)
    {
        T type;
        var serializer = new XmlSerializer(typeof(T));
        using (var reader = XmlReader.Create(path))
        {
            type = serializer.Deserialize(reader) as T;
        }
        return type;
    }
}

其它参考9


我们的想法是为反序列化处理所有级别
请参阅解决我类似问题的示例解决方案


<?xml version="1.0" ?> 
 <TRANSACTION_RESPONSE>
    <TRANSACTION>
        <TRANSACTION_ID>25429</TRANSACTION_ID> 
        <MERCHANT_ACC_NO>02700701354375000964</MERCHANT_ACC_NO> 
        <TXN_STATUS>F</TXN_STATUS> 
        <TXN_SIGNATURE>a16af68d4c3e2280e44bd7c2c23f2af6cb1f0e5a28c266ea741608e72b1a5e4224da5b975909cc43c53b6c0f7f1bbf0820269caa3e350dd1812484edc499b279</TXN_SIGNATURE> 
        <TXN_SIGNATURE2>B1684258EA112C8B5BA51F73CDA9864D1BB98E04F5A78B67A3E539BEF96CCF4D16CFF6B9E04818B50E855E0783BB075309D112CA596BDC49F9738C4BF3AA1FB4</TXN_SIGNATURE2> 
        <TRAN_DATE>29-09-2015 07:36:59</TRAN_DATE> 
        <MERCHANT_TRANID>150929093703RUDZMX4</MERCHANT_TRANID> 
        <RESPONSE_CODE>9967</RESPONSE_CODE> 
        <RESPONSE_DESC>Bank rejected transaction!</RESPONSE_DESC> 
        <CUSTOMER_ID>RUDZMX</CUSTOMER_ID> 
        <AUTH_ID /> 
        <AUTH_DATE /> 
        <CAPTURE_DATE /> 
        <SALES_DATE /> 
        <VOID_REV_DATE /> 
        <REFUND_DATE /> 
        <REFUND_AMOUNT>0.00</REFUND_AMOUNT> 
    </TRANSACTION>
  </TRANSACTION_RESPONSE> 


上面的XML分为两个级别


  [XmlType("TRANSACTION_RESPONSE")]
public class TransactionResponse
{
    [XmlElement("TRANSACTION")]
    public BankQueryResponse Response { get; set; }

}


内在的水平


public class BankQueryResponse
{
    [XmlElement("TRANSACTION_ID")]
    public string TransactionId { get; set; }

    [XmlElement("MERCHANT_ACC_NO")]
    public string MerchantAccNo { get; set; }

    [XmlElement("TXN_SIGNATURE")]
    public string TxnSignature { get; set; }

    [XmlElement("TRAN_DATE")]
    public DateTime TranDate { get; set; }

    [XmlElement("TXN_STATUS")]
    public string TxnStatus { get; set; }


    [XmlElement("REFUND_DATE")]
    public DateTime RefundDate { get; set; }

    [XmlElement("RESPONSE_CODE")]
    public string ResponseCode { get; set; }


    [XmlElement("RESPONSE_DESC")]
    public string ResponseDesc { get; set; }

    [XmlAttribute("MERCHANT_TRANID")]
    public string MerchantTranId { get; set; }

}


同样的方式你需要多个级别car as array
检查此示例以进行多级反序列化

其它参考10


如果您使用xsd.exe创建xsd文件时出错,请使用msdn中提到的XmlSchemaInference类。这是一个单元测试来演示:[54]


using System.Xml;
using System.Xml.Schema;

[TestMethod]
public void GenerateXsdFromXmlTest()
{
    string folder = @"C:\mydir\mydata\xmlToCSharp";
    XmlReader reader = XmlReader.Create(folder + "\some_xml.xml");
    XmlSchemaSet schemaSet = new XmlSchemaSet();
    XmlSchemaInference schema = new XmlSchemaInference();

    schemaSet = schema.InferSchema(reader);


    foreach (XmlSchema s in schemaSet.Schemas())
    {
        XmlWriter xsdFile = new XmlTextWriter(folder + "\some_xsd.xsd", System.Text.Encoding.UTF8);
        s.Write(xsdFile);
        xsdFile.Close();
    }
}

// now from the visual studio command line type: xsd some_xsd.xsd /classes

其它参考11


您可以为您更改汽车汽车属性的一个属性,从XmlArrayItem到XmlElment。也就是说,来自


[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlArrayItem(typeof(Car))]
    public Car[] Car { get; set; }
}





[System.Xml.Serialization.XmlRootAttribute("Cars", Namespace = "", IsNullable = false)]
public class Cars
{
    [XmlElement("Car")]
    public Car[] Car { get; set; }
}

其它参考12


我的解决方案



  1. 使用Edit > Past Special > Paste XML As Classes获取代码中的课程

  2. 尝试这样的事情:创建该类的列表(List<class1>),然后使用XmlSerializer将该列表序列化为xml文件。

  3. 现在您只需用您的数据替换该文件的正文并尝试deserialize它。



码:


StreamReader sr = new StreamReader(@"C:\Users\duongngh\Desktop\Newfolder\abc.txt");
XmlSerializer xml = new XmlSerializer(typeof(Class1[]));
var a = xml.Deserialize(sr);
sr.Close();


注意:你必须注意根名称,不要改变它。我的是ArrayOfClass1

其它参考13


初学者



我发现这里的答案非常有帮助,说我仍然努力(只是一点点)让这个工作。所以,万一它可以帮助别人,我会说明工作解决方案:


来自原始问题的XML。 xml位于文件Class1.xml中,此文件的path用于代码中以查找此xml文件。


我使用了@erymski的答案来实现这一点,因此创建了一个名为Car.cs的文件并添加了以下内容:



using System.Xml.Serialization;  // Added

public class Car
{
    public string StockNumber { get; set; }
    public string Make { get; set; }
    public string Model { get; set; }
}

[XmlRootAttribute("Cars")]
public class CarCollection
{
    [XmlElement("Car")]
    public Car[] Cars { get; set; }
}



@erymski提供的另一部分代码......



using (TextReader reader = new StreamReader(path))
{
  XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
  return (CarCollection) serializer.Deserialize(reader);
}



...进入你的主程序(Program.cs),在static CarCollection XCar()中如下:


using System;
using System.IO;
using System.Xml.Serialization;

namespace ConsoleApp2
{
    class Program
    {

        public static void Main()
        {
            var c = new CarCollection();

            c = XCar();

            foreach (var k in c.Cars)
            {
                Console.WriteLine(k.Make + " " + k.Model + " " + k.StockNumber);
            }
            c = null;
            Console.ReadLine();

        }
        static CarCollection XCar()
        {
            using (TextReader reader = new StreamReader(@"C:\Users\SlowLearner\source\repos\ConsoleApp2\ConsoleApp2\Class1.xml"))
            {
                XmlSerializer serializer = new XmlSerializer(typeof(CarCollection));
                return (CarCollection)serializer.Deserialize(reader);
            }
        }
    }
}


希望能帮助到你 :-)

其它参考14


如何反序列化XML文档的泛型类


//++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
// Generic class to load any xml into a class
// used like this ...
// YourClassTypeHere InfoList = LoadXMLFileIntoClass<YourClassTypeHere>(xmlFile);

using System.IO;
using System.Xml.Serialization;

public static T LoadXMLFileIntoClass<T>(string xmlFile)
{
    T returnThis;
    XmlSerializer serializer = new XmlSerializer(typeof(T));
    if (!FileAndIO.FileExists(xmlFile))
    {
        Console.WriteLine("FileDoesNotExistError {0}", xmlFile);
    }
    returnThis = (T)serializer.Deserialize(new StreamReader(xmlFile));
    return (T)returnThis;
}


这部分可能是,也可能不是必要的。在Visual Studio中打开XML文档,右键单击XML,选择属性。然后选择您的架构文件。